Math Problem Statement

can you solve the problems?

can you solve the problems?

Solution

Sure, let's solve these problems one by one.

  1. Evaluate the expression (2+3)24(31)(2 + \sqrt{3})^2 - 4(\sqrt{3} - 1).

    (2+3)2=4+43+3=7+43(2 + \sqrt{3})^2 = 4 + 4\sqrt{3} + 3 = 7 + 4\sqrt{3}

    4(31)=4344(\sqrt{3} - 1) = 4\sqrt{3} - 4

    Subtract the two results:

    (7+43)(434)=7+4=11(7 + 4\sqrt{3}) - (4\sqrt{3} - 4) = 7 + 4 = 11

    Answer: A) 11

  2. Find the allowable values for the expression x+74x\frac{x+7}{\sqrt{4-x}}.

    The expression is valid when the denominator is positive:

    4x>04x>0x<4\sqrt{4 - x} > 0 \Rightarrow 4 - x > 0 \Rightarrow x < 4

    Answer: Г) x<4x < 4

  3. Find the roots of the equation x2+9=13\sqrt{x^2 + 9} = \sqrt{13}.

    Square both sides:

    x2+9=13x^2 + 9 = 13

    x2=4x^2 = 4

    x=±2x = \pm 2

    Answer: A) -2 and 2

  4. The expression sin2(90α)+sin2α1\sin^2(90^\circ - \alpha) + \sin^2 \alpha - 1 is identically equal to:

    Using identities: sin(90α)=cosα\sin(90^\circ - \alpha) = \cos \alpha

    cos2α+sin2α=1\cos^2 \alpha + \sin^2 \alpha = 1

    (cos2α+sin2α)1=0(\cos^2 \alpha + \sin^2 \alpha) - 1 = 0

    Answer: В) 0

  5. The sequence {an}\{a_n\} is defined by a1=2a_1 = 2 and an+1=2an1a_{n+1} = 2a_n - 1. Find the sum of the first three terms.

    a1=2a_1 = 2

    a2=2×21=3a_2 = 2 \times 2 - 1 = 3

    a3=2×31=5a_3 = 2 \times 3 - 1 = 5

    Sum = a1+a2+a3=2+3+5=10a_1 + a_2 + a_3 = 2 + 3 + 5 = 10

    Answer: В) 10

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Math Problem Analysis

Mathematical Concepts

Algebra
Trigonometry
Sequences and Series
Radicals

Formulas

(a + b)^2 = a^2 + 2ab + b^2
sin(90° - α) = cos(α)
cos^2(α) + sin^2(α) = 1
a_{n+1} = 2a_n - 1

Theorems

Pythagorean Identity
Algebraic Expansion

Suitable Grade Level

Grades 9-12