Math Problem Statement

Solving for angles based on bisectors and algebraic equations for different examples involving bisected angles.

Solution

The examples and diagram you've provided focus on solving angle bisectors and equations for angles.

Here’s a breakdown of the examples based on the images:

Example 3:

Given:

  • mDEG=88m \angle DEG = 88^\circ
  • EFEF bisects DEG\angle DEG, which means FEG\angle FEG is half of DEG\angle DEG.

Thus, mFEG=12×88=44m \angle FEG = \frac{1}{2} \times 88^\circ = 44^\circ.

The provided answer 4444^\circ is correct.

Example 4:

Given:

  • mFED=27m \angle FED = 27^\circ
  • EFEF bisects DEG\angle DEG, and we need to find mGEDm \angle GED.

Since EFEF is the bisector, both mFEDm \angle FED and mGEDm \angle GED are equal.

So, mGED=27m \angle GED = 27^\circ.

The answer 5454^\circ written in the example likely refers to the sum of the two angles ( mFED+mGEDm \angle FED + m \angle GED).

Example 5:

Given:

  • mDEF=3x+1m \angle DEF = 3x + 1
  • mDEG=5x+19m \angle DEG = 5x + 19

Since EFEF bisects DEG\angle DEG, we have: mDEF+mFEG=mDEGm \angle DEF + m \angle FEG = m \angle DEG But because EFEF bisects the angle, the two parts should be equal. We can write: 3x+1+3x+1=5x+193x + 1 + 3x + 1 = 5x + 19 Simplifying: 6x+2=5x+196x + 2 = 5x + 19 Subtract 5x5x from both sides: x+2=19x + 2 = 19 Subtract 2 from both sides: x=17x = 17

Thus, x=17x = 17.

Example 6:

Given:

  • mDEF=5x3m \angle DEF = 5x - 3
  • mFEG=2x+15m \angle FEG = 2x + 15

Since EFEF bisects DEG\angle DEG, the two angles are equal: 5x3=2x+155x - 3 = 2x + 15 Solving for xx: Subtract 2x2x from both sides: 3x3=153x - 3 = 15 Add 3 to both sides: 3x=183x = 18 Divide by 3: x=6x = 6

Thus, x=6x = 6.

Example 7:

Given:

  • mFEG=6x7m \angle FEG = 6x - 7
  • mFED=2x+41m \angle FED = 2x + 41

We need to solve for xx first.

Since EFEF bisects DEG\angle DEG, the two angles are equal: 6x7=2x+416x - 7 = 2x + 41 Solving for xx: Subtract 2x2x from both sides: 4x7=414x - 7 = 41 Add 7 to both sides: 4x=484x = 48 Divide by 4: x=12x = 12

Now, to find mDEGm \angle DEG, sum the two angles: mFEG+mFED=(6x7)+(2x+41)m \angle FEG + m \angle FED = (6x - 7) + (2x + 41) Substitute x=12x = 12: (6(12)7)+(2(12)+41)=(727)+(24+41)=65+65=130(6(12) - 7) + (2(12) + 41) = (72 - 7) + (24 + 41) = 65 + 65 = 130^\circ

Thus, mDEG=130m \angle DEG = 130^\circ.


Would you like further details on any of these solutions?

5 Follow-up Questions:

  1. How is an angle bisector used to split an angle into two equal parts?
  2. Can you explain how solving for xx helps in finding the value of an angle?
  3. What role does substitution play in checking the final angle?
  4. How does combining like terms simplify solving equations?
  5. Why is it important to verify the values of all angles in a bisected diagram?

Tip:

Always check your work by plugging the value of xx back into the original expressions to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Angle Bisectors
Algebraic Equations
Linear Equations

Formulas

Angle Bisector: If EF bisects angle DEG, then m∠DEF = m∠FEG
Sum of Angles: m∠DEF + m∠FEG = m∠DEG
Linear Equation: Solve for x in the form of ax + b = cx + d

Theorems

Angle Bisector Theorem: A bisector divides an angle into two equal parts
Properties of Equality: Used for solving algebraic equations

Suitable Grade Level

Grade 8-10