Math Problem Statement

Let​ a, b,​ c, and x be real numbers. a. How is solving StartAbsoluteValue ax EndAbsoluteValue plus b equals c different from solving StartAbsoluteValue ax plus b EndAbsoluteValue equals c​? b. How is solving StartAbsoluteValue ax EndAbsoluteValue plus b less than or equals c different from solving StartAbsoluteValue ax plus b EndAbsoluteValue greater than or equals c​? Question content area bottom Part 1 a. How is solving StartAbsoluteValue ax EndAbsoluteValue plus b equals c different from solving StartAbsoluteValue ax plus b EndAbsoluteValue equals c​? A. When solving StartAbsoluteValue ax EndAbsoluteValue plus b equals c​, b has to be subtracted from both sides first to isolate the absolute value expression. B. Solving StartAbsoluteValue ax plus b EndAbsoluteValue equals c involves solving two equations that do not have absolute values. Solving StartAbsoluteValue ax EndAbsoluteValue plus b equals c involves solving only one such equation. C. Solving StartAbsoluteValue ax EndAbsoluteValue plus b equals c involves solving two equations that do not have absolute values. Solving StartAbsoluteValue ax plus b EndAbsoluteValue equals c involves solving only one such equation. D. When solving StartAbsoluteValue ax plus b EndAbsoluteValue equals c​, b has to be subtracted from both sides first to isolate the absolute value expression.

Solution

Part 1a: Understanding the Differences

Let's break down the two equations to understand how they differ in terms of solving them:

  1. Equation 1: ax+b=c|ax| + b = c

    • Step: The first step is to isolate the absolute value expression. To do this, you subtract bb from both sides: ax=cb|ax| = c - b
    • Next Step: Now, you can proceed by splitting this into two cases, since ax=cb|ax| = c - b implies: ax=cborax=(cb)ax = c - b \quad \text{or} \quad ax = -(c - b)
    • Finally, solve for xx in both cases.
  2. Equation 2: ax+b=c|ax + b| = c

    • Step: Here, the absolute value expression is already isolated. Therefore, you can immediately split this into two cases: ax+b=corax+b=cax + b = c \quad \text{or} \quad ax + b = -c
    • Next Step: Solve each equation for xx by isolating xx in both cases.

Choosing the Correct Answer:

  • Option A: Correct. For ax+b=c|ax| + b = c, you need to subtract bb first to isolate the absolute value expression.
  • Option B: Incorrect. Both forms involve solving two linear equations when you remove the absolute values.
  • Option C: Incorrect. This is the reverse of the correct scenario.
  • Option D: Incorrect. The description is correct for ax+b=c|ax + b| = c, but the situation described doesn't fit.

Correct Answer: A.

Follow-Up

Would you like further details or have any questions? Here are some related questions to deepen your understanding:

  1. How do the solutions change if cc is negative in ax+b=c|ax + b| = c?
  2. What is the geometric interpretation of ax+b=c|ax| + b = c versus ax+b=c|ax + b| = c?
  3. How does the solution process change if b>cb > c in ax+b=c|ax| + b = c?
  4. What happens if b=0b = 0 in both equations?
  5. How do these approaches change if the equation involves inequalities instead of equalities?

Tip: Always isolate the absolute value expression first before

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Equations
Inequalities

Formulas

|ax| + b = c
|ax + b| = c
|ax| + b ≤ c
|ax + b| ≥ c

Theorems

Properties of Absolute Value
Solving Absolute Value Equations
Solving Inequalities

Suitable Grade Level

Grades 8-10