Math Problem Statement
Solution
The given equation is , and the question asks for when , based on the conditions given for .
We are looking for the values of under which holds. Let's analyze each option carefully:
Step 1: Analyzing the equation
The equation is , and it simplifies to: If , raising both sides of the equation to the power of , implies that , unless some restrictions or specific values of and change this behavior.
So, we are essentially looking for cases where under specific values of .
Step 2: Checking the options
Option (a) and
If , then , and the equation becomes , because any power of 1 remains 1. Therefore, , which satisfies the condition. Hence, option (a) is true.
Option (b) and
If , then does not guarantee unless and are equal, which contradicts the condition . Hence, option (b) is false.
Option (c) and
If is negative and , this would lead to issues with taking powers of negative numbers (depending on whether is an integer or not). Even in cases where powers are defined, would not hold. Hence, option (c) is false.
Option (d) and
This option is contradictory because it says but also . This is impossible. Hence, option (d) is false.
Conclusion:
The correct answer is (a), where and .
Would you like further details or have any questions about this? Here are some related questions you might consider:
- How would the solution change if were zero?
- What if instead of ?
- How does the solution change for non-integer exponents?
- What would happen if were a complex number?
- How would the equation behave if negative powers were involved?
Tip: When dealing with exponentials and variable bases, always consider special cases like or , as they often simplify the equation greatly.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Exponents
Algebra
Formulas
a^b = x^b
Theorems
Exponentiation rules
Suitable Grade Level
Grades 9-12