Math Problem Statement

\cos (x-(\pi )/(4))-\cos (x+(\pi )/(4))=\sqrt(2)\sin x

Solution

We are tasked with solving the following trigonometric equation:

cos(xπ4)cos(x+π4)=2sinx\cos \left( x - \frac{\pi}{4} \right) - \cos \left( x + \frac{\pi}{4} \right) = \sqrt{2} \sin x

Step 1: Use the cosine difference identity

We can apply the following identity for the difference of cosines: cosAcosB=2sin(A+B2)sin(AB2)\cos A - \cos B = -2 \sin \left( \frac{A+B}{2} \right) \sin \left( \frac{A-B}{2} \right)

Let A=xπ4A = x - \frac{\pi}{4} and B=x+π4B = x + \frac{\pi}{4}. Using this identity, we get:

cos(xπ4)cos(x+π4)=2sin((xπ4)+(x+π4)2)sin((xπ4)(x+π4)2)\cos \left( x - \frac{\pi}{4} \right) - \cos \left( x + \frac{\pi}{4} \right) = -2 \sin \left( \frac{\left(x - \frac{\pi}{4}\right) + \left(x + \frac{\pi}{4}\right)}{2} \right) \sin \left( \frac{\left(x - \frac{\pi}{4}\right) - \left(x + \frac{\pi}{4}\right)}{2} \right)

Step 2: Simplify the terms

The first term becomes: (xπ4)+(x+π4)2=2x2=x\frac{\left(x - \frac{\pi}{4}\right) + \left(x + \frac{\pi}{4}\right)}{2} = \frac{2x}{2} = x The second term becomes: (xπ4)(x+π4)2=π22=π4\frac{\left(x - \frac{\pi}{4}\right) - \left(x + \frac{\pi}{4}\right)}{2} = \frac{-\frac{\pi}{2}}{2} = -\frac{\pi}{4}

Thus, the equation simplifies to: 2sinxsin(π4)=2sinx-2 \sin x \sin \left( -\frac{\pi}{4} \right) = \sqrt{2} \sin x

Step 3: Simplify further

Since sin(π4)=22\sin \left( -\frac{\pi}{4} \right) = -\frac{\sqrt{2}}{2}, we can substitute this into the equation:

2sinx(22)=2sinx-2 \sin x \cdot \left( -\frac{\sqrt{2}}{2} \right) = \sqrt{2} \sin x

This simplifies to:

2sinx=2sinx\sqrt{2} \sin x = \sqrt{2} \sin x

Step 4: Conclusion

The equation is an identity, meaning it is true for all values of xx. Therefore, the solution is:

xRx \in \mathbb{R}


Would you like more details on any step or have any specific questions?

Related Questions:

  1. How can we apply the sum-to-product identities to other trigonometric equations?
  2. What are some real-world applications of trigonometric identities?
  3. How do you solve a trigonometric equation involving both sine and cosine functions?
  4. How can you derive the cosine and sine difference identities?
  5. What is the general solution to sinx=0\sin x = 0 and cosx=0\cos x = 0?

Tip: Always double-check your trigonometric identities and ensure you apply the correct one when simplifying equations.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities

Formulas

cos(A) - cos(B) = -2sin((A + B)/2)sin((A - B)/2)
sin(-\frac{\pi}{4}) = -\frac{\sqrt{2}}{2}

Theorems

Cosine Difference Identity
Sine of Negative Angles

Suitable Grade Level

Grades 10-12