Math Problem Statement

Two triangles can be formed using the given measurements. The other measurements of the triangle in which angle B is acute are also given. Solve the triangle in which angle B is obtuse. Aequals=4444degrees°   aequals=99   bequals=1111 Question content area bottom Part 1 For the first​ triangle, the angle B is 58.158.1degrees°​, the measure of angle C is 77.977.9degrees°​, and the length of side c is 12.712.7. Now consider the second triangle. The measure of angle B is enter your response heredegrees°. ​(Round to the nearest tenth as​ needed.)

Solution

To solve the triangle in which angle BB is obtuse, we will use the Law of Sines and the information given for the triangle.

Given:

  • A=44A = 44^\circ
  • a=9a = 9
  • b=11b = 11

First, let's calculate angle BB when it is acute using the Law of Sines: asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B}

9sin44=11sinB\frac{9}{\sin 44^\circ} = \frac{11}{\sin B}

Solving for sinB\sin B: sinB=11sin449\sin B = \frac{11 \sin 44^\circ}{9}

Calculating sin44\sin 44^\circ (using a calculator): sin440.694\sin 44^\circ \approx 0.694

Now, substituting the value: sinB=11×0.69497.63490.848\sin B = \frac{11 \times 0.694}{9} \approx \frac{7.634}{9} \approx 0.848

Therefore: Bsin1(0.848)58.1B \approx \sin^{-1}(0.848) \approx 58.1^\circ

Given that there is a second triangle where BB is obtuse, we calculate the obtuse angle by: B=18058.1=121.9B = 180^\circ - 58.1^\circ = 121.9^\circ

Now, we find the remaining angle CC: C=180ABC = 180^\circ - A - B

For the obtuse triangle: C=18044121.9=14.1C = 180^\circ - 44^\circ - 121.9^\circ = 14.1^\circ

Lastly, let's calculate the side cc using the Law of Sines: csinC=asinA\frac{c}{\sin C} = \frac{a}{\sin A}

Rearranging to solve for cc: c=asinCsinAc = \frac{a \cdot \sin C}{\sin A}

Substituting the known values: sinC=sin14.10.244\sin C = \sin 14.1^\circ \approx 0.244 c=90.2440.6943.16c = \frac{9 \cdot 0.244}{0.694} \approx 3.16

So, the measurements for the triangle in which BB is obtuse are:

  • A=44A = 44^\circ
  • B=121.9B = 121.9^\circ
  • C=14.1C = 14.1^\circ
  • a=9a = 9
  • b=11b = 11
  • c=3.2c = 3.2 (rounded to the nearest tenth)

Would you like more details or have any questions?

Here are some related questions to expand your understanding:

  1. What is the Law of Sines and how is it used in solving triangles?
  2. How do you determine if an angle in a triangle is obtuse or acute?
  3. Can the Law of Cosines be used to solve this triangle? If so, how?
  4. How would the solution differ if side aa was longer than side bb?
  5. What are the properties of an obtuse triangle?
  6. How do you calculate the area of a triangle given two sides and the included angle?
  7. How can you verify the accuracy of your calculations in trigonometric problems?
  8. What are some real-life applications of solving triangles?

Tip: When solving triangles using trigonometric functions, ensure your calculator is set to the correct mode (degrees or radians) based on the given angles.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Triangle Solving

Formulas

Law of Sines: \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \)

Theorems

Triangle Angle Sum Theorem

Suitable Grade Level

High School