Math Problem Statement
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. There may be two triangles, one triangle, or no triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Enter all angles in degrees. Round your answers to one decimal place. Below, enter your answers so that ∠A1 is smaller than ∠A2.) b = 24, c = 38, ∠B = 24° ∠A1
Incorrect: Your answer is incorrect. ° ∠A2
Incorrect: Your answer is incorrect. ° ∠C1
Incorrect: Your answer is incorrect. ° ∠C2
Incorrect: Your answer is incorrect. ° a1
Incorrect: Your answer is incorrect. a2
Incorrect: Your answer is incorrect.
Solution
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Law of Sines
Ambiguous Case of Triangles
Formulas
Law of Sines: (a / sin A) = (b / sin B) = (c / sin C)
Angle Sum of a Triangle: A + B + C = 180°
Ambiguous Case: Sin A1 and Sin A2 for non-right triangles
Theorems
Law of Sines
Ambiguous Case in Trigonometry
Suitable Grade Level
Grades 10-12
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