Math Problem Statement

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In triangle ABC, you are given the following information: Angle A = 30°, Side a = 10 units (opposite angle A), Side c = 12 units (opposite angle C), and Side b is unknown but is said to be equal to the sum of angles A and C in degrees. Using the sine rule, find the measure of angle B. After that, verify if triangle ABC is valid with the triangle inequality. If it is valid, calculate the length of side b and then find angle C using the sine rule.

Solution

Let's solve this step-by-step.

Step 1: Understanding Given Information

For triangle ABCABC:

  • A=30\angle A = 30^\circ
  • a=10a = 10 units (side opposite angle AA)
  • c=12c = 12 units (side opposite angle CC)
  • Side bb is unknown but said to be equal to the sum of A\angle A and C\angle C in degrees.

We will:

  1. Use the sine rule to find B\angle B.
  2. Verify if triangle ABCABC satisfies the triangle inequality.
  3. If valid, find the length of bb and then C\angle C using the sine rule.

Step 2: Using the Sine Rule to Find B\angle B

The sine rule states: asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} Let's first use asinA=csinC\frac{a}{\sin A} = \frac{c}{\sin C} to find C\angle C because bb depends on the sum of A\angle A and C\angle C in degrees.

  1. Setting up the equation: 10sin30=12sinC\frac{10}{\sin 30^\circ} = \frac{12}{\sin C}

    Since sin30=0.5\sin 30^\circ = 0.5, this simplifies to: 100.5=12sinC\frac{10}{0.5} = \frac{12}{\sin C} 20=12sinC20 = \frac{12}{\sin C} sinC=1220=0.6\sin C = \frac{12}{20} = 0.6

  2. Finding C\angle C: C=sin1(0.6)36.87C = \sin^{-1}(0.6) \approx 36.87^\circ

Step 3: Calculating bb

Since bb is said to be equal to the sum of A\angle A and C\angle C in degrees: b=30+36.87=66.87b = 30^\circ + 36.87^\circ = 66.87^\circ

Step 4: Using the Sine Rule to Find B\angle B

Now, we know:

  • A=30\angle A = 30^\circ
  • C36.87\angle C \approx 36.87^\circ
  • B=1803036.87\angle B = 180^\circ - 30^\circ - 36.87^\circ

Calculating B\angle B: B18066.87=113.13B \approx 180^\circ - 66.87^\circ = 113.13^\circ

Step 5: Verify the Triangle Inequality

For triangle inequality to hold:

  • a+b>ca + b > c
  • a+c>ba + c > b
  • b+c>ab + c > a

Substituting:

  1. 10+66.87>1210 + 66.87 > 12 — True
  2. 10+12>66.8710 + 12 > 66.87 — False (This inequality does not hold)

Since the triangle inequality is not satisfied, triangle ABCABC is not valid with the given values of sides and angles.


If you have any further questions or would like more details, please let me know!

Additional Questions

  1. How would the solution change if side bb were defined differently?
  2. Can the sine rule be applied if only two angles are known?
  3. How can we determine if a triangle is valid without calculating side lengths?
  4. What is the significance of the triangle inequality in geometry?
  5. How would the solution proceed if the triangle were valid?

Tip

When solving for unknown angles or sides in triangles, always check if the solution satisfies the triangle inequality to confirm validity.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Triangle Inequality
Sine Rule

Formulas

Sine rule: \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \)
Triangle inequality: For any triangle, the sum of the lengths of any two sides must be greater than the length of the remaining side

Theorems

Sine Rule
Triangle Inequality

Suitable Grade Level

Grades 10-12