Math Problem Statement

solve tan (2pi/3)

Solution

To solve tan(2π3)\tan\left(\frac{2\pi}{3}\right), follow these steps:

  1. Convert the angle to degrees (optional): 2π3 radians=2×1803=120\frac{2\pi}{3} \text{ radians} = \frac{2 \times 180^\circ}{3} = 120^\circ However, since the trigonometric functions can be directly computed in radians, this step is not necessary.

  2. Use the reference angle: The angle 2π3\frac{2\pi}{3} is in the second quadrant. The reference angle is: π2π3=π3\pi - \frac{2\pi}{3} = \frac{\pi}{3}

  3. Evaluate tan(π3)\tan(\frac{\pi}{3}): tan(π3)=3\tan\left(\frac{\pi}{3}\right) = \sqrt{3}

  4. Determine the sign in the second quadrant: In the second quadrant, tangent is negative. Therefore: tan(2π3)=3\tan\left(\frac{2\pi}{3}\right) = -\sqrt{3}

So, the solution is: tan(2π3)=3\tan\left(\frac{2\pi}{3}\right) = -\sqrt{3}

Would you like more details on any step, or do you have any questions?

Here are 5 related questions you might find interesting:

  1. What is tan(4π3)\tan\left(\frac{4\pi}{3}\right)?
  2. How do you solve sin(2π3)\sin\left(\frac{2\pi}{3}\right)?
  3. What are the trigonometric values for π/3\pi/3 in each quadrant?
  4. How do you convert between radians and degrees?
  5. What is the general solution for tan(θ)=3\tan(\theta) = \sqrt{3}?

Tip: Always remember the signs of trigonometric functions in each quadrant to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Trigonometry

Formulas

Tangent of angles in different quadrants

Theorems

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Suitable Grade Level

High School