Math Problem Statement
Solve T(n) = 9T(n/6) + n log^2 n, by master method. (10 marks)
Solution
Let's solve the recurrence relation using the Master Theorem for divide-and-conquer recurrences.
The recurrence is of the form: Where:
To apply the Master Theorem, we compare with .
Step 1: Calculate
We need to compute . Using the change of base formula: We approximate: Thus: So, .
Step 2: Compare with
We now compare the asymptotic behavior of with :
- grows slightly slower than , because is times a polylogarithmic term, while has a strictly larger exponent of .
Step 3: Apply Master Theorem
The Master Theorem cases are:
- Case 1: If for some , then .
- Case 2: If for some , then .
- Case 3: If for some and if for some constant and sufficiently large , then .
In this case, is asymptotically smaller than but not polynomially smaller. Therefore, we are in Case 2 of the Master Theorem. Hence, the solution to the recurrence is:
Final Answer:
The solution to the recurrence by the Master Method is:
Would you like any additional details or clarifications?
Here are 5 related questions:
- How does the Master Theorem handle logarithmic factors in ?
- What conditions are needed for each case of the Master Theorem to apply?
- How do we handle non-standard functions like in recurrence relations?
- Can the Master Theorem be applied to all recurrences?
- How does the change of base formula help in solving recurrences with non-integer bases?
Tip: When solving recurrence relations, carefully compare the growth rates of the terms to choose the correct case of the Master Theorem.
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Math Problem Analysis
Mathematical Concepts
Recurrence Relations
Master Theorem
Asymptotic Analysis
Formulas
Master Theorem for Divide-and-Conquer Recurrences
Theorems
Master Theorem
Suitable Grade Level
Advanced Undergraduate