Math Problem Statement

Given the system of equations: a + b + c = 4, a^2 + b^2 + c^2 = 10, a^3 + b^3 + c^3 = 22, find the value of a^4 + b^4 + c^4.

Solution

We are given the following system of equations:

a+b+c=4a + b + c = 4 a2+b2+c2=10a^2 + b^2 + c^2 = 10 a3+b3+c3=22a^3 + b^3 + c^3 = 22 We are tasked with finding the value of a4+b4+c4a^4 + b^4 + c^4.

Step 1: Use Elementary Symmetric Polynomials

We start by recognizing that these equations can be handled using symmetric polynomials. Define:

  • p1=a+b+cp_1 = a + b + c
  • p2=ab+bc+cap_2 = ab + bc + ca
  • p3=abcp_3 = abc

Given:

  • p1=4p_1 = 4

We will use the relations for power sums: a2+b2+c2=p122p2a^2 + b^2 + c^2 = p_1^2 - 2p_2 Substituting the known values: 10=422p210 = 4^2 - 2p_2 10=162p210 = 16 - 2p_2 Solving for p2p_2: p2=3p_2 = 3

Step 2: Use the Third Equation

We can express a3+b3+c3a^3 + b^3 + c^3 in terms of p1,p2,p3p_1, p_2, p_3: a3+b3+c3=p133p1p2+3p3a^3 + b^3 + c^3 = p_1^3 - 3p_1p_2 + 3p_3 Substitute the known values: 22=433(4)(3)+3p322 = 4^3 - 3(4)(3) + 3p_3 22=6436+3p322 = 64 - 36 + 3p_3 22=28+3p322 = 28 + 3p_3 Solving for p3p_3: p3=2p_3 = -2

Step 3: Find a4+b4+c4a^4 + b^4 + c^4

We can express a4+b4+c4a^4 + b^4 + c^4 as: a4+b4+c4=(a2+b2+c2)22(a2b2+b2c2+c2a2)a^4 + b^4 + c^4 = (a^2 + b^2 + c^2)^2 - 2(a^2b^2 + b^2c^2 + c^2a^2) We already know that a2+b2+c2=10a^2 + b^2 + c^2 = 10, so: a4+b4+c4=1022(a2b2+b2c2+c2a2)a^4 + b^4 + c^4 = 10^2 - 2(a^2b^2 + b^2c^2 + c^2a^2) Now, we calculate a2b2+b2c2+c2a2a^2b^2 + b^2c^2 + c^2a^2 using: a2b2+b2c2+c2a2=p222p1p3a^2b^2 + b^2c^2 + c^2a^2 = p_2^2 - 2p_1p_3 Substitute the known values: a2b2+b2c2+c2a2=322(4)(2)a^2b^2 + b^2c^2 + c^2a^2 = 3^2 - 2(4)(-2) a2b2+b2c2+c2a2=9+16=25a^2b^2 + b^2c^2 + c^2a^2 = 9 + 16 = 25

Finally, substitute this into the expression for a4+b4+c4a^4 + b^4 + c^4: a4+b4+c4=1002(25)=10050=50a^4 + b^4 + c^4 = 100 - 2(25) = 100 - 50 = 50

Thus, the value of a4+b4+c4a^4 + b^4 + c^4 is 50\boxed{50}.


Would you like further details on any step? Here are some related questions to consider:

  1. How can the method of symmetric polynomials be applied to higher-degree equations?
  2. What is the general form of the power sum symmetric polynomials?
  3. Could these results help in solving cubic or quartic equations?
  4. What other techniques can solve similar systems of equations?
  5. How would the approach differ if the equations were non-symmetric?

Tip: In problems involving powers of variables and sums, symmetric polynomials simplify the work by reducing the number of variables and focusing on key invariants.

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Math Problem Analysis

Mathematical Concepts

Symmetric Polynomials
Power Sums
Elementary Algebra

Formulas

a^2 + b^2 + c^2 = p_1^2 - 2p_2
a^3 + b^3 + c^3 = p_1^3 - 3p_1p_2 + 3p_3
a^4 + b^4 + c^4 = (a^2 + b^2 + c^2)^2 - 2(a^2b^2 + b^2c^2 + c^2a^2)

Theorems

Power Sum Symmetric Polynomials

Suitable Grade Level

Grades 10-12