The given system of linear equations is:

$2x - 3y = -1$ $y = x - 1$

To solve this, we can substitute the second equation $y = x - 1$ into the first equation:

1. Substitute $y = x - 1$ into $2x - 3y = -1$: $2x - 3(x - 1) = -1$

2. Simplify the equation: $2x - 3x + 3 = -1$

3. Combine like terms: $-x + 3 = -1$

4. Solve for $x$: $-x = -1 - 3$ $-x = -4 \quad \Rightarrow \quad x = 4$

5. Now, substitute $x = 4$ into the second equation $y = x - 1$: $y = 4 - 1 = 3$

So, the solution is $(x, y) = (4, 3)$.

The correct answer from the given choices is (4, 3).

Would you like more details or have any other questions?

Here are five related questions:

1. How do you solve a system of equations using substitution in general?
2. What is the method of elimination, and how is it different from substitution?
3. How can you check if your solution to a system of linear equations is correct?
4. Can a system of linear equations have no solution or infinitely many solutions?
5. What is the graphical interpretation of solving a system of two linear equations?

Tip: Substitution is often useful when one equation is already solved for a variable, as it simplifies the process.