Math Problem Statement

the sum of two numbers is 42. The sum of the smaller and 4 times the larger is 147. Find the numbers

Solution

Let the two numbers be xx (smaller) and yy (larger). We can write the problem as a system of two equations:

  1. x+y=42x + y = 42
  2. x+4y=147x + 4y = 147

Step 1: Solve for xx in terms of yy from the first equation

From x+y=42x + y = 42,
x=42yx = 42 - y

Step 2: Substitute x=42yx = 42 - y into the second equation

Substitute into x+4y=147x + 4y = 147:
(42y)+4y=147(42 - y) + 4y = 147 Simplify:
42+3y=14742 + 3y = 147 3y=1053y = 105 y=35y = 35

Step 3: Solve for xx

Substitute y=35y = 35 into x=42yx = 42 - y:
x=4235x = 42 - 35 x=7x = 7

Final Answer:

The two numbers are:
Smaller number: x=7x = 7
Larger number: y=35y = 35


Would you like further clarification or details on any step?

Related Questions:

  1. How do you solve systems of linear equations using substitution?
  2. Can the problem be solved using the elimination method instead?
  3. What are other word problems involving systems of equations?
  4. How can this problem be visualized graphically?
  5. How can we verify the solution?

Tip:

Always check your solution by substituting the values back into the original equations to ensure they satisfy both equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations

Formulas

x + y = 42
x + 4y = 147

Theorems

Substitution Method for Solving Equations

Suitable Grade Level

Grades 8-10