Math Problem Statement
x − y + z = 1 Equation 1 2x − y − 2z = 3 Equation 2 x + 3y − 3z = −1 solve using elimination
Solution
We are given the system of equations:
Step 1: Eliminate one variable (let's eliminate )
First, subtract Equation 1 from Equation 2 to eliminate :
Simplifying:
Next, subtract Equation 1 from Equation 3 to eliminate :
Simplifying: Dividing by 2:
Step 2: Solve the system of two equations
Now we have the reduced system:
- (Equation 4)
- (Equation 5)
Solve for in terms of from Equation 4:
Solve for in terms of from Equation 5:
Step 3: Substitute into the original equation
Now that we have and , substitute these into Equation 1 to find :
Simplifying:
Step 4: Solve for and
Now that we know , we can substitute this value into the expressions for and :
Final Solution:
Would you like further details or have any questions?
Here are 5 related questions to explore:
- How can substitution be used to solve this system?
- What happens if you choose to eliminate instead of ?
- How does elimination compare to solving systems graphically?
- Can this method be applied to larger systems of equations?
- What real-world problems can be modeled by systems of equations?
Tip: Always double-check each step of elimination to avoid sign errors!
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
Systems of Equations
Elimination Method
Formulas
Linear Equation: ax + by + cz = d
Elimination of variables by subtraction
Theorems
Elimination Method for Systems of Equations
Suitable Grade Level
Grades 9-11
Related Recommendation
Solving Systems of Equations Using Elimination: Algebraic Solution
Solving a System of Linear Equations: x - y + z = -1; x + y + 3z = -3; 2x - y + 2z = 0
Solving a 3-Variable System of Equations Using the Elimination Method
Step-by-Step Solution to a System of Linear Equations
Solving a System of Linear Equations Using Elimination