Math Problem Statement

Solve the system of linear equations: -6x + 3y - z = 5, 3x - y + 5z = -10, x + 2y + 3z = -1.

Solution

The system of equations shown in the image is:

1. & \quad -6x + 3y - z = 5 \\ 2. & \quad 3x - y + 5z = -10 \\ 3. & \quad x + 2y + 3z = -1 \end{align*}$$ To solve this system of linear equations, I will use the elimination or substitution method to find the values of $$x$$, $$y$$, and $$z$$. Let me calculate that for you. The solution to the system of equations is: $$x = \frac{31}{59}, \quad y = \frac{123}{59}, \quad z = \frac{-112}{59}$$ These are the exact values for $$x$$, $$y$$, and $$z$$. Would you like to see the steps in detail, or do you have any other questions? Here are some related questions for deeper understanding: 1. How do we apply the substitution method to solve systems of equations? 2. What is the geometric interpretation of solving a system of three linear equations? 3. Can Gaussian elimination be used to solve this system? How? 4. How do you check if the solution to a system of equations is unique? 5. What happens if the system of equations has no solution or infinitely many solutions? **Tip:** Always verify the solution by plugging the values of $$x$$, $$y$$, and $$z$$ back into the original equations.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Systems of Equations
Algebra

Formulas

Substitution Method
Elimination Method
Cramer's Rule

Theorems

Fundamental Theorem of Algebra
Gaussian Elimination

Suitable Grade Level

Grades 9-12