Math Problem Statement
أوجد حل النظام الآتي باستخدام كرامر:
3x + 2y = 6
-x + y = 4
Solution
The problem presented in the image requires solving the system of equations using Cramer's rule. The given system of equations is:
Step-by-Step Solution Using Cramer's Rule:
Step 1: Write the system in matrix form
The system of equations can be written in matrix form as:
3 & 2 \\ -1 & 1 \end{pmatrix} \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 6 \\ 4 \end{pmatrix}$$ Here, the coefficient matrix $$A$$ is: $$A = \begin{pmatrix} 3 & 2 \\ -1 & 1 \end{pmatrix}$$ and the constant matrix $$B$$ is: $$B = \begin{pmatrix} 6 \\ 4 \end{pmatrix}$$ #### Step 2: Calculate the determinant of matrix $$A$$, $$\Delta$$ The determinant of $$A$$ is: $$\Delta = \text{det}(A) = \begin{vmatrix} 3 & 2 \\ -1 & 1 \end{vmatrix} = (3)(1) - (2)(-1) = 3 + 2 = 5$$ #### Step 3: Calculate $$\Delta_x$$ and $$\Delta_y$$ Now, calculate the determinants $$\Delta_x$$ and $$\Delta_y$$ by replacing the respective columns of matrix $$A$$ with the constants from matrix $$B$$. - For $$\Delta_x$$, replace the first column of $$A$$ with $$B$$: $$A_x = \begin{pmatrix} 6 & 2 \\ 4 & 1 \end{pmatrix}$$ $$\Delta_x = \text{det}(A_x) = \begin{vmatrix} 6 & 2 \\ 4 & 1 \end{vmatrix} = (6)(1) - (2)(4) = 6 - 8 = -2$$ - For $$\Delta_y$$, replace the second column of $$A$$ with $$B$$: $$A_y = \begin{pmatrix} 3 & 6 \\ -1 & 4 \end{pmatrix}$$ $$\Delta_y = \text{det}(A_y) = \begin{vmatrix} 3 & 6 \\ -1 & 4 \end{vmatrix} = (3)(4) - (6)(-1) = 12 + 6 = 18$$ #### Step 4: Solve for $$x$$ and $$y$$ Using Cramer's rule: $$x = \frac{\Delta_x}{\Delta} = \frac{-2}{5} = -\frac{2}{5}$$ $$y = \frac{\Delta_y}{\Delta} = \frac{18}{5} = \frac{18}{5}$$ ### Final Answer: $$x = -\frac{2}{5}, \quad y = \frac{18}{5}$$ --- Would you like any further details or clarifications? Here are some related questions for you to consider: 1. How is Cramer's rule different from other methods of solving systems of equations? 2. Can you always use Cramer's rule for any system of equations? 3. What happens if the determinant $$\Delta$$ is zero? 4. How would you solve this system of equations using substitution or elimination instead of Cramer's rule? 5. What are the advantages of using matrix methods like Cramer's rule in larger systems of equations? **Tip:** Cramer's rule is particularly useful for small systems of linear equations (2x2 or 3x3) but becomes computationally expensive for larger systems.Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear Equations
Matrix Algebra
Cramer's Rule
Formulas
Cramer's Rule
Determinant of a 2x2 Matrix
Theorems
Cramer's Rule
Suitable Grade Level
Grades 10-12