It appears you have a system of linear equations. Let’s write them in a clearer format:

1. $3x + 3y = 15$
2. $12x + 8y = 20$

We can solve this system using either substitution, elimination, or matrix methods. Here, elimination might be straightforward since both equations can be simplified.

Step 1: Simplify Each Equation

1. For the first equation: $3x + 3y = 15$ $x + y = 5$

2. For the second equation: $12x + 8y = 20$ $3x + 2y = 5$

Now we have a simplified system:

1. $x + y = 5$
2. $3x + 2y = 5$

Step 2: Solve the System by Elimination

Multiply the first equation by 2 to eliminate $y$ when we subtract:

$2x + 2y = 10$ $3x + 2y = 5$

Subtract the first equation from the second:

$(3x + 2y) - (2x + 2y) = 5 - 10$ $x = -5$

Step 3: Substitute $x = -5$ into $x + y = 5$

$-5 + y = 5$ $y = 10$

Solution

The solution to the system is: $x = -5, \quad y = 10$

Would you like more details or have questions on this solution?

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Here are 5 related questions that might interest you:

1. How do you solve systems of equations using matrix methods?
2. What is the importance of simplifying equations before solving?
3. How does substitution compare to elimination in solving systems?
4. Can systems of equations have no solution or infinitely many solutions?
5. How can systems of equations be represented graphically?

Tip: Always check if you can simplify equations first; it often makes solving much easier!