Let's solve the system of equations:

1. $y = -6 - 7$
2. $4x - y = 3$

Step 1: Simplify the first equation

The first equation can be simplified:

$y = -13$

Step 2: Substitute $y = -13$ into the second equation

Substitute $y = -13$ into the second equation $4x - y = 3$:

$4x - (-13) = 3$

$4x + 13 = 3$

Step 3: Solve for $x$

Isolate $x$ by subtracting 13 from both sides:

$4x = 3 - 13$

$4x = -10$

Now, divide by 4:

$x = -\frac{10}{4} = -\frac{5}{2}$

Final Answer:

The solution to the system is $x = -\frac{5}{2}$ and $y = -13$.

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Would you like more details or have any questions? Here are some related problems:

1. Solve the system: $y = 2x + 5$ and $3x - y = 7$.
2. Solve the system: $y = 4x - 9$ and $2x + y = 11$.
3. Solve for $x$ and $y$: $y = 3x + 1$ and $5x - y = 14$.
4. Find the intersection point of the lines $y = -x + 2$ and $y = 2x - 4$.
5. Solve for $x$ and $y$: $y = -2x + 3$ and $4x + 2y = 8$.

Tip: When solving systems of equations, substitution or elimination methods are commonly used to find the solution.