Math Problem Statement

solve by substitution

Solve by substitution: y = x^2 - 5x + 5 and y = 5x - 20

Solution

from PIL import Image import pytesseract

Load the image to extract text

image_path = '/mnt/data/1732501454290pc2lnw1j.jpg' extracted_text = pytesseract.image_to_string(Image.open(image_path))

extracted_text'y=r—Sr+5\ny=5r—20\n''y=r—Sr+5\ny=5r—20\n'successThe equations extracted from the image are:

  1. y=x25x+5y = x^2 - 5x + 5
  2. y=5x20y = 5x - 20

Solving by substitution:

Since yy is equal in both equations, we can set the right-hand sides of the equations equal to each other:

x25x+5=5x20x^2 - 5x + 5 = 5x - 20

Simplify the equation:

x25x5x+5+20=0x^2 - 5x - 5x + 5 + 20 = 0 x210x+25=0x^2 - 10x + 25 = 0

Factorize the quadratic equation:

(x5)(x5)=0(x - 5)(x - 5) = 0

So, x=5x = 5 (a repeated root).

Find yy using y=5x20y = 5x - 20:

y=5(5)20=2520=5y = 5(5) - 20 = 25 - 20 = 5

Solution:

The point of intersection is: (x,y)=(5,5)(x, y) = (5, 5)

Would you like a detailed step-by-step explanation or graphical representation of this? Here are some related questions:

  1. How do you verify the solution of a substitution problem?
  2. What happens if the equations describe parallel lines?
  3. Can you explain substitution in a system with more variables?
  4. How can we graphically confirm the solution?
  5. What if the quadratic equation had two distinct roots?

Tip: Always double-check your solution by substituting back into the original equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
System of Equations

Formulas

Quadratic equation formula ax^2 + bx + c = 0

Theorems

Properties of quadratic equations
Substitution method for systems of equations

Suitable Grade Level

Grades 9-10