Math Problem Statement

Solve the following task No. 2 with solving ABC triangle using this method provided in the photo. And get the following answers: Angle A= 65.0 degrees, Angle B= 25.0 degrees, and side a= 29.4cm!

Solve the following task No. 2 with solving ABC triangle using this method provided in the photo. And get the following answers: Angle A= 65.0 degrees, Angle B= 25.0 degrees, and side a= 29.4cm.

Solution

To solve the given task (Triangle ABC) using the provided methods, we'll follow the steps outlined in the textbook images and confirm the required values:

  • Given:
    • Angle A=65.0A = 65.0^\circ
    • Angle B=25.0B = 25.0^\circ
    • Side a=29.4cma = 29.4 \, \text{cm}

We need to determine the missing sides bb and cc, and confirm the angles.

Step 1: Verify the angles

The sum of angles in any triangle is 180180^\circ.

We are given A=65.0A = 65.0^\circ and B=25.0B = 25.0^\circ. Therefore, we can calculate angle CC as: C=180AB=18065.025.0=90C = 180^\circ - A - B = 180^\circ - 65.0^\circ - 25.0^\circ = 90^\circ Since it's a right triangle, C=90C = 90^\circ, which matches the given information.

Step 2: Use Trigonometric Ratios

Since this is a right triangle, we can apply the sine, cosine, and tangent functions to find the missing sides.

Find side cc (the hypotenuse):

We use the sine function to relate side aa (opposite AA) and the hypotenuse cc: sinA=ac\sin A = \frac{a}{c} Rearranging to solve for cc: c=asinA=29.4cmsin65.0c = \frac{a}{\sin A} = \frac{29.4 \, \text{cm}}{\sin 65.0^\circ} Using a calculator: sin65.00.9063\sin 65.0^\circ \approx 0.9063 c=29.40.906332.43cmc = \frac{29.4}{0.9063} \approx 32.43 \, \text{cm}

Find side bb (adjacent to angle AA):

We use the tangent function to relate sides aa and bb: tanA=ab\tan A = \frac{a}{b} Rearranging to solve for bb: b=atanA=29.4cmtan65.0b = \frac{a}{\tan A} = \frac{29.4 \, \text{cm}}{\tan 65.0^\circ} Using a calculator: tan65.02.1445\tan 65.0^\circ \approx 2.1445 b=29.42.144513.71cmb = \frac{29.4}{2.1445} \approx 13.71 \, \text{cm}

Final Answer:

  • Angle A=65.0A = 65.0^\circ
  • Angle B=25.0B = 25.0^\circ
  • Angle C=90C = 90^\circ
  • Side a=29.4cma = 29.4 \, \text{cm} (Given)
  • Side b=13.71cmb = 13.71 \, \text{cm}
  • Side c=32.43cmc = 32.43 \, \text{cm}

Let me know if you'd like more details, or if you have any questions!

Here are five related questions to deepen your understanding:

  1. How do you derive the Pythagorean theorem from a right triangle like this one?
  2. What happens to the sine and cosine ratios as the angle AA approaches 9090^\circ?
  3. If you were given side bb instead of side aa, how would you solve for the remaining sides?
  4. Can you explain the connection between tangent and sine/cosine in trigonometric ratios?
  5. What are some real-world applications of solving right triangles?

Tip: Always check the sum of the angles in any triangle to ensure correctness, especially in right triangles where one angle should always be 9090^\circ.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangle
Trigonometric Ratios
Sine
Cosine
Tangent

Formulas

sin(θ) = opposite/hypotenuse
cos(θ) = adjacent/hypotenuse
tan(θ) = opposite/adjacent
Pythagorean Theorem: a² + b² = c²

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-9