Let the length of the rectangle be $L$ cm and the breadth be $B$ cm.

Step 1: Express the relationship between length and breadth

According to the problem, the length $L$ is 4 cm more than twice the breadth $B$. This can be written as: $L = 2B + 4$

Step 2: Use the perimeter formula

The perimeter $P$ of a rectangle is given by: $P = 2(L + B)$ The problem states that the perimeter is 26 cm, so: $2(L + B) = 26$ Dividing both sides by 2: $L + B = 13$

Step 3: Substitute the expression for $L$

From Step 1, we know $L = 2B + 4$, so substitute this into $L + B = 13$: $(2B + 4) + B = 13$ Simplify: $3B + 4 = 13$ Subtract 4 from both sides: $3B = 9$ Divide by 3: $B = 3 \text{ cm}$

Step 4: Find $L$

Now, substitute $B = 3$ into the equation for $L$: $L = 2(3) + 4 = 6 + 4 = 10 \text{ cm}$

Final Answer:

• Length $L = 10$ cm
• Breadth $B = 3$ cm

Would you like a more detailed explanation, or do you have any questions?

Here are 5 related questions:

1. What is the area of the rectangle?
2. How would the dimensions change if the perimeter was 40 cm?
3. What if the length was 6 cm more than twice the breadth?
4. How would you calculate the diagonal of the rectangle?
5. How does the perimeter formula relate to that of a square?

Tip: Always check if the equation you set up correctly reflects the conditions given in the problem.