The given equation is:

\[
1000 = \frac{1}{R C}
\]

To solve for either \( R \) (resistance) or \( C \) (capacitance), you can rearrange the equation. Let's solve for \( R \) and \( C \):

### 1. Solving for \( R \):

\[
R = \frac{1}{1000 C}
\]

This gives the resistance \( R \) in terms of the capacitance \( C \).

### 2. Solving for \( C \):

\[
C = \frac{1}{1000 R}
\]

This gives the capacitance \( C \) in terms of the resistance \( R \).

Both \( R \) and \( C \) are inversely proportional to each other.

Let me know if you want to go deeper into a specific case! Here are some questions related to this:

1. What are the typical values of \( R \) and \( C \) in practical circuits?
2. How does the frequency of a circuit affect \( R \) and \( C \)?
3. Can you provide specific values for \( R \) or \( C \) to calculate the other?
4. How is this formula related to time constants in RC circuits?
5. What are the physical interpretations of \( R \) and \( C \) in an electrical circuit?

**Tip:** The product of \( R \) and \( C \) defines the time constant \( \tau \) of an RC circuit, which influences how quickly the circuit responds to changes in voltage.

This page explores how to solve the equation 1000 = 1/RC, a fundamental formula in electronics, for resistance (R) and capacitance (C). It explains how R and C are inversely proportional, along with practical applications of the RC time constant. Suitable for Grades 10-12 students studying electronics and algebra.

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