https://file.aiquickdraw.com/mathbot/file/1725364458796ihdddk60.jpg

The expression in the image is:

\[
y = \frac{x + 3}{2x - 1}
\]

To solve for \(y\), this equation is already solved for \(y\) in terms of \(x\). Therefore, \(y\) is a function of \(x\) given by the above expression.

### To evaluate this function for a specific value of \(x\):
1. Substitute the value of \(x\) into the equation.
2. Simplify the expression to find the corresponding value of \(y\).

For example, if you want to evaluate \(y\) at \(x = 2\):

\[
y = \frac{2 + 3}{2(2) - 1} = \frac{5}{4 - 1} = \frac{5}{3}
\]

So, \(y = \frac{5}{3}\) when \(x = 2\).

Would you like more details on how to work with this type of function, or do you have any specific questions?

### Related Questions:
1. What is the value of \(y\) when \(x = 0\) in this function?
2. How does the function \(y = \frac{x + 3}{2x - 1}\) behave as \(x\) approaches infinity?
3. Are there any values of \(x\) for which this function is undefined?
4. How do you find the inverse of this function?
5. What are the asymptotes of the function \(y = \frac{x + 3}{2x - 1}\)?

### Tip:
When dealing with rational functions, it's crucial to identify points where the function might be undefined, typically where the denominator equals zero.

Learn how to solve the rational function y = (x + 3) / (2x - 1) with a detailed step-by-step solution. Understand how to evaluate the function for specific values of x, find points where the function is undefined, and explore its behavior as x approaches infinity. Suitable for high school students in Grades 10-12.

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