Math Problem Statement

solve rational functions step by step which the given is f (x)=2/x-1

Solution

To solve and analyze the rational function f(x)=2x1f(x) = \frac{2}{x} - 1 step by step, we'll break it down into key aspects: domain, simplifying, finding asymptotes, intercepts, and the behavior of the function.

Step 1: Identify the Domain

The domain of the function is all the possible values of xx for which the function is defined. Since there is a fraction with xx in the denominator, we must ensure that xx is not equal to 0 (because division by zero is undefined).

Domain: xRx \in \mathbb{R} except x0x \neq 0

Step 2: Simplify the Function (if possible)

The given function is f(x)=2x1f(x) = \frac{2}{x} - 1. This function is already simplified; no further simplification is necessary.

Step 3: Find Asymptotes

Vertical Asymptote: Vertical asymptotes occur where the denominator of the rational function equals zero, which makes the function undefined.

  • Set the denominator equal to zero: x=0x = 0
  • So, there is a vertical asymptote at x=0x = 0.

Horizontal Asymptote: For rational functions, the horizontal asymptote depends on the degrees of the polynomial in the numerator and denominator.

  • The degree of the numerator is 0 (constant 2) and the degree of the denominator is 1 (since xx is in the denominator).
  • Since the degree of the denominator is greater, the horizontal asymptote is y=0y = 0.

Step 4: Find the Intercepts

x-intercept: The x-intercept occurs where f(x)=0f(x) = 0.

  • Set the function equal to 0: 2x1=0\frac{2}{x} - 1 = 0
  • Solve for xx: 2x=1    x=2\frac{2}{x} = 1 \implies x = 2
  • So, the x-intercept is at (2,0)(2, 0).

y-intercept: The y-intercept occurs where x=0x = 0, but since x=0x = 0 is not in the domain, the function has no y-intercept.

Step 5: Analyze the Function's Behavior

To understand how the function behaves as xx approaches the asymptotes and other critical points:

  • As xx approaches 0 from the right (x0+)(x \to 0^+), f(x)+f(x) \to +\infty.
  • As xx approaches 0 from the left (x0)(x \to 0^-), f(x)f(x) \to -\infty.
  • As xx approaches \infty, f(x)1f(x) \to -1.
  • As xx approaches -\infty, f(x)1f(x) \to -1.

This means the function gets closer to -1 as xx increases or decreases in magnitude, but it never actually reaches -1.

Summary of the Function's Properties

  • Domain: xR,x0x \in \mathbb{R}, x \neq 0
  • Vertical Asymptote: x=0x = 0
  • Horizontal Asymptote: y=1y = -1
  • x-intercept: (2,0)(2, 0)
  • y-intercept: None

Would you like to go over any specific part of this solution, or do you have any questions?

Relative Questions

  1. How do you determine the horizontal asymptote of a rational function?
  2. What happens to the value of f(x)f(x) as xx approaches infinity?
  3. How would you graph the function f(x)=2x1f(x) = \frac{2}{x} - 1?
  4. Can a function have more than one vertical asymptote? Under what conditions?
  5. What are the general steps to finding the intercepts of a rational function?

Tip

When analyzing rational functions, always check for both vertical and horizontal asymptotes to understand the function's behavior at extreme values of xx.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Domain
Asymptotes
Intercepts

Formulas

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Theorems

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Suitable Grade Level

Grades 11-12