https://file.aiquickdraw.com/mathbot/file/1726903179342re6ig9dc.jpg

The equation given in the image is:

\[
\sqrt{x + 5} = 8
\]

To solve for \( x \), follow these steps:

1. **Square both sides** of the equation to eliminate the square root:

\[
(\sqrt{x + 5})^2 = 8^2
\]

This simplifies to:

\[
x + 5 = 64
\]

2. **Subtract 5 from both sides** to isolate \( x \):

\[
x = 64 - 5
\]

\[
x = 59
\]

Thus, the solution is \( x = 59 \).

Would you like further details or have any questions?

Here are some related questions to consider:
1. How would you solve if the equation were \( \sqrt{x + 3} = 7 \)?
2. What happens if the square root has a negative number inside it?
3. How would you solve \( \sqrt{x - 2} = 9 \)?
4. What if you have \( \sqrt{2x + 5} = 10 \)?
5. Can you solve \( \sqrt{x + 4} = -5 \)? Why or why not?

**Tip**: Always remember to check your solutions by plugging the value back into the original equation to ensure accuracy.

Learn how to solve the radical equation √(x + 5) = 8 by squaring both sides and isolating x. This problem demonstrates key algebraic concepts like solving square roots and basic equation manipulation, suitable for Grades 8-10.

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