Math Problem Statement
2次不等式 x^2+3x+2 > 0 ... ① と, 2次関数 f(x)=x^2-2x-a^2+6α-3がある。ただし、aは定数とする。2次不等式①を満たすxの値の範囲において,y=f(x) のグラフがx軸とただ1つの共有点をもつようなαの値の範囲を求めよ。
Solution
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Inequalities
Quadratic Functions
Discriminant
Formulas
Factorization: x^2 + 3x + 2 = (x + 1)(x + 2)
Quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / 2a
Discriminant: D = b^2 - 4ac
Theorems
Quadratic Discriminant Theorem
Condition for a quadratic function to have one solution
Suitable Grade Level
Grades 10-12
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