Math Problem Statement

no bro, ur forgetting the inequality, we have to do smt with that, it is Ax^2 +Bx+C is greater than or equal to 0

Solution

You're right! If we are dealing with the inequality Ax2+Bx+C0Ax^2 + Bx + C \geq 0, here's how we proceed:

Step-by-Step Solution

  1. Determine the nature of the roots:

    • Calculate the discriminant: Δ=B24AC\Delta = B^2 - 4AC.
    • Based on Δ\Delta:
      • If Δ>0\Delta > 0: Two distinct real roots exist.
      • If Δ=0\Delta = 0: One real root (a double root) exists.
      • If Δ<0\Delta < 0: No real roots exist (parabola does not touch the xx-axis).
  2. Analyze the parabola's direction:

    • If A>0A > 0, the parabola opens upwards.
    • If A<0A < 0, the parabola opens downwards.
  3. Critical points:

    • If Δ0\Delta \geq 0: Find the roots x1x_1 and x2x_2 using the quadratic formula: x1,x2=B±Δ2A.x_1, x_2 = \frac{-B \pm \sqrt{\Delta}}{2A}.
  4. Sign of the inequality:

    • For Ax2+Bx+C0Ax^2 + Bx + C \geq 0:
      • If the parabola opens upwards (A>0A > 0):
        • The solution is (,x1][x2,)(-\infty, x_1] \cup [x_2, \infty) when Δ>0\Delta > 0.
        • If Δ=0\Delta = 0: The solution is x=x1x = x_1 (the double root).
        • If Δ<0\Delta < 0: The solution is all real numbers ((,)(-\infty, \infty)).
      • If the parabola opens downwards (A<0A < 0):
        • The solution is [x1,x2][x_1, x_2] when Δ>0\Delta > 0.
        • If Δ=0\Delta = 0: The solution is x=x1x = x_1.
        • If Δ<0\Delta < 0: The solution is the empty set (\emptyset).
  5. Boundary handling:

    • If the inequality is strict (Ax2+Bx+C>0Ax^2 + Bx + C > 0), exclude the roots from the solution (replace brackets with parentheses in the intervals).

Would you like me to work through a specific example or provide a graph of this situation? Let me know!

5 Related Questions:

  1. What happens to the inequality if AA or CC is zero?
  2. Can you demonstrate graphically why the solution intervals depend on Δ\Delta?
  3. How would the solution change for Ax2+Bx+C0Ax^2 + Bx + C \leq 0?
  4. What role does completing the square play in solving this inequality?
  5. How do inequalities involving \geq differ from strict inequalities involving >>?

Tip:

Always check the discriminant first to quickly determine the nature of the parabola and how it affects the inequality solution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Inequalities
Parabolas

Formulas

Discriminant formula: Δ = B^2 - 4AC
Quadratic formula: x = (-B ± √Δ) / 2A

Theorems

Quadratic Formula Theorem
Sign Analysis of Quadratic Expressions

Suitable Grade Level

Grades 10-12