To find the value of the expression $9y^2 + 6y - 5$ when $y = 2$, we substitute $y = 2$ into the expression:

$9(2)^2 + 6(2) - 5$

1. First, calculate $9(2)^2$: $9 \times 4 = 36$

2. Next, calculate $6(2)$: $6 \times 2 = 12$

3. Now substitute these values back into the expression: $36 + 12 - 5$

4. Simplify the expression: $36 + 12 = 48$ $48 - 5 = 43$

So, the value of the expression is $43$.

Would you like further details or explanations?

Here are 5 related questions you might want to explore:

1. What is the general form of a quadratic expression?
2. How do you factor a quadratic equation like $9y^2 + 6y - 5$?
3. What is the discriminant, and how is it used in quadratic equations?
4. How can you graph the expression $9y^2 + 6y - 5$?
5. What happens to the expression if $y = -2$ instead of $y = 2$?

Tip: Always follow the order of operations (PEMDAS) when evaluating expressions: Parentheses, Exponents, Multiplication/Division (left to right), Addition/Subtraction (left to right).