Math Problem Statement

x2x^2+2=4

Solution

To solve the equation x2+2=4x^2 + 2 = 4, follow these steps:

  1. Subtract 2 from both sides of the equation:

    x2+22=42x^2 + 2 - 2 = 4 - 2

    Simplifying both sides, we get:

    x2=2x^2 = 2

  2. Take the square root of both sides:

    x=±2x = \pm \sqrt{2}

The solutions to the equation x2+2=4x^2 + 2 = 4 are x=2x = \sqrt{2} and x=2x = -\sqrt{2}.

Would you like more details or have any questions? Here are some related questions you might want to ask:

  1. How do you solve quadratic equations by factoring?
  2. Can you explain how to complete the square to solve quadratic equations?
  3. What are the steps to solve quadratic equations using the quadratic formula?
  4. How do you determine the nature of the roots of a quadratic equation?
  5. Can you provide examples of solving cubic equations?

Tip: When solving equations involving squares, always remember to consider both the positive and negative roots.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Quadratic equation formula: ax^2 + bx + c = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 7-9