The given equation is:

\[
(x - 4)^2 + 8 = 0
\]

To express this in the standard quadratic form \(Ax^2 + Bx + C = 0\), we first need to expand and simplify the equation.

1. Expand \((x - 4)^2\):

\[
(x - 4)(x - 4) = x^2 - 8x + 16
\]

2. Substitute this back into the equation:

\[
x^2 - 8x + 16 + 8 = 0
\]

3. Combine like terms:

\[
x^2 - 8x + 24 = 0
\]

Now, the equation is in the standard quadratic form \(Ax^2 + Bx + C = 0\), where:

- \(A = 1\)
- \(B = -8\)
- \(C = 24\)

Would you like more details or have any questions?

Here are some related questions:
1. How do you solve the quadratic equation \(x^2 - 8x + 24 = 0\)?
2. What are the roots of the quadratic equation \(x^2 - 8x + 24 = 0\)?
3. How does the discriminant help in determining the nature of the roots?
4. What is the vertex form of a quadratic equation?
5. How do you complete the square for \(x^2 - 8x + 24\)?

**Tip:** When dealing with quadratic equations, always ensure you expand and simplify fully to identify the coefficients \(A\), \(B\), and \(C\).

Learn how to solve the quadratic equation (x-4)^2 + 8 = 0 with a step-by-step solution. This problem involves expanding and simplifying quadratic expressions and identifying coefficients A, B, and C. Suitable for students in Grades 9-12.

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