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The solutions to the equation \( g(x) = -5 \) for \( g(x) = -0.3x^2 + 3x + 6 \) are:

\[
x = -2.8528, 12.8528
\]

Both solutions are rounded to four decimal places.

Would you like further details or have any questions?

Here are five related questions:
1. How do you solve quadratic equations in general?
2. What are the different methods to solve a quadratic equation?
3. Why is it important to round solutions to a certain number of decimal places?
4. Can quadratic equations have complex solutions, and how do you find them?
5. How does changing the coefficient of \( x^2 \) affect the graph of a quadratic equation?

**Tip:** Always check the discriminant \( b^2 - 4ac \) before solving quadratics to determine the nature of the solutions (real or complex).

Solve the equation g(x) = -5 for x if g(x) = -0.3x^2 + 3x + 6.

Learn how to solve the quadratic equation -0.3x^2 + 3x + 6 = -5 using the quadratic formula. This example includes step-by-step instructions and provides solutions rounded to four decimal places. Perfect for students in Grades 9-12.

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