Math Problem Statement

Solve the proportion for the missing value represented by a letter (represented as dots in the image). The proportion involves mixed fractions and is displayed as: (4 1/3)/(1/9) = (5/...)/(4 2/3).

Solution

The problem in the first image shows a proportion that needs to be solved for the missing term, represented by dots. Here's the given proportion:

41319=4235\frac{\frac{4 \frac{1}{3}}{\frac{1}{9}}} = \frac{\dots}{\frac{4 \frac{2}{3}}{5}}

Step-by-Step Solution:

1. Convert mixed numbers to improper fractions:

  • 413=1334 \frac{1}{3} = \frac{13}{3}
  • 423=1434 \frac{2}{3} = \frac{14}{3}

So, the proportion becomes:

13319=1435\frac{\frac{\frac{13}{3}}{\frac{1}{9}}} = \frac{\dots}{\frac{\frac{14}{3}}{5}}

2. Simplify the complex fractions:

  • 13319=133×91=13×93×1=1173=39\frac{\frac{13}{3}}{\frac{1}{9}} = \frac{13}{3} \times \frac{9}{1} = \frac{13 \times 9}{3 \times 1} = \frac{117}{3} = 39
  • 1435=143×15=14×13×5=1415\frac{\frac{14}{3}}{5} = \frac{14}{3} \times \frac{1}{5} = \frac{14 \times 1}{3 \times 5} = \frac{14}{15}

Now the equation becomes:

39=141539 = \frac{\dots}{\frac{14}{15}}

3. Solve for the missing term (\dots):

  • Multiply both sides by 1415\frac{14}{15} to isolate the missing term:

=39×1415\dots = 39 \times \frac{14}{15}

4. Calculate the missing term:

  • 39×1415=39×1415=54615=36.439 \times \frac{14}{15} = \frac{39 \times 14}{15} = \frac{546}{15} = 36.4

Final Answer:

The missing term is 36.436.4.

Would you like a more detailed explanation or have any questions?


Here are 5 related questions to explore this concept further:

  1. How do you simplify complex fractions?
  2. What is the process of converting mixed numbers to improper fractions?
  3. How can proportions be applied in real-world problems?
  4. What is the significance of cross-multiplication in solving proportions?
  5. What are some alternative methods for solving proportions?

Tip: When solving proportions involving mixed numbers, always convert them to improper fractions first to make calculations easier.

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Math Problem Analysis

Mathematical Concepts

Fractions
Proportions
Mixed Numbers
Complex Fractions

Formulas

Convert mixed numbers to improper fractions
Simplify complex fractions
Cross-multiplication in proportions

Theorems

Basic Proportion Theorem

Suitable Grade Level

Grade 8-10