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The question states that Tyas has the same amount of money as \( \frac{3}{2} \) times Mariz's money. If their total money is Rp 35,000, we need to find how much money Tyas has.

Let's denote Mariz's money as \( M \). According to the problem, Tyas's money can be expressed as \( \frac{3}{2}M \).

Given the total amount of their money:
\[ M + \frac{3}{2}M = 35,000 \]

Let's solve this equation to find \( M \) and consequently find Tyas's amount.

\[ \frac{5}{2}M = 35,000 \]
\[ M = \frac{35,000 \times 2}{5} \]
\[ M = 14,000 \]

Thus, Tyas's money is:
\[ \frac{3}{2}M = \frac{3}{2} \times 14,000 = 21,000 \]

Therefore, Tyas has Rp 21,000.

Would you like more details on this calculation or do you have any other questions on this topic? Here are some related questions you might find interesting:

1. What would be Tyas's amount if the total money was different, say Rp 50,000?
2. How does the proportion \( \frac{3}{2} \) affect the distribution of money between Tyas and Mariz?
3. If Mariz had three times less money than Tyas, how would you set up and solve that equation?
4. Can you solve for how many percent more money Tyas has compared to Mariz?
5. What if there were three people sharing the money and the relations between their amounts were given similarly?

Tip: When dealing with proportions in money sharing problems, it's often helpful to represent unknown amounts with variables and set up a linear equation based on the total sum given.

Uang Tyas sama dengan 3/2 uang Mariz. Jika jumlah uang mereka Rp 35.000, maka uang Tyas adalah?

Learn how to solve a problem where Tyas's money is 3/2 of Mariz's, with their total amount being Rp 35,000. This algebraic problem involves solving proportions and linear equations. Suitable for Grades 6-8.

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