Math Problem Statement

-4t^2 + t - 6 = 0. Find the roots and plot them on the graph.

Solution

The image contains a problem that involves finding the roots of a quadratic equation and plotting them on a graph. Let's break down and solve the problem step by step.

Problem Details:

  1. The quadratic equation given is: 4t2+t6=0-4t^2 + t - 6 = 0
  2. The instructions seem to ask for the roots of the equation and plotting these roots on the provided graph.

Step 1: Solve the Quadratic Equation

The general form of a quadratic equation is: at2+bt+c=0at^2 + bt + c = 0 For the given equation: 4t2+t6=0-4t^2 + t - 6 = 0 Here, a=4a = -4, b=1b = 1, and c=6c = -6.

To find the roots, we can use the quadratic formula: t=b±b24ac2at = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Plugging in the values: t=1±124(4)(6)2(4)t = \frac{-1 \pm \sqrt{1^2 - 4(-4)(-6)}}{2(-4)} t=1±1968t = \frac{-1 \pm \sqrt{1 - 96}}{-8} t=1±958t = \frac{-1 \pm \sqrt{-95}}{-8}

Step 2: Analyze the Discriminant

The discriminant Δ=b24ac\Delta = b^2 - 4ac is negative (Δ=95\Delta = -95), which means the equation has no real roots but rather complex roots.

Step 3: Plotting on the Graph

Since the roots are complex, they cannot be plotted on a real number line, which is what the grid provided seems to represent.

Conclusion:

The equation does not have real roots, so nothing should be plotted on the graph for real-number roots.


Would you like any further details on how to solve quadratic equations with complex roots, or have any questions about this problem? Here are five related questions:

  1. How do you find the roots of a quadratic equation with a negative discriminant?
  2. What do complex roots represent in a quadratic equation?
  3. How can the quadratic formula be derived from the standard form

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Quadratic equation formula t = (-b ± sqrt(b^2 - 4ac)) / 2a

Theorems

Quadratic Formula
Discriminant Analysis

Suitable Grade Level

Grades 9-12