Math Problem Statement

Find the missing side lengths and angle measures in the given parallelograms and rhombuses.

Solution

Let’s solve the problems step by step based on the image.


Problem 13:

In parallelogram CDEF, if CG = 9, find CE.

  • In a parallelogram, the diagonals bisect each other.
    This means that CG = GE.
    Therefore, CE=CG+GE=9+9=18CE = CG + GE = 9 + 9 = 18.
    Answer: CE=18CE = 18.

Problem 14:

In parallelogram QRST, if RT = 36, find RU.

  • Similar to Problem 13, the diagonals of a parallelogram bisect each other.
    Thus, RU=RT2=362=18RU = \frac{RT}{2} = \frac{36}{2} = 18.
    Answer: RU=18RU = 18.

Problem 15:

Find the measure of the three missing angles in the rhombus.

  • The angles of a rhombus are supplementary when adjacent, and diagonals bisect opposite angles.

  • The given angle is 5858^\circ:

    • The opposite angle is also 5858^\circ.
    • The adjacent angles are supplementary to 5858^\circ:
      18058=122180^\circ - 58^\circ = 122^\circ.

    Answer:
    x=58x = 58^\circ,
    y=122y = 122^\circ,
    z=58z = 58^\circ.


Problem 16:

Find the values of xx, yy, and zz in the rhombus.

  • In a rhombus, opposite angles are equal, and adjacent angles are supplementary.

    • x+49=90x + 49 = 90 (since the rhombus forms a right angle at one diagonal intersection).
      Solve: x=9049=41x = 90 - 49 = 41.
    • y+6=90y + 6 = 90.
      Solve: y=906=84y = 90 - 6 = 84.
    • z10=90z - 10 = 90.
      Solve: z=90+10=100z = 90 + 10 = 100.

    Answer:
    x=41x = 41,
    y=84y = 84,
    z=100z = 100.


Problem 17:

Find the values of xx, yy, and zz in the rhombus.

  • In a rhombus, adjacent angles are supplementary.

    • Given 10x+110x + 1 and 5959, we solve:
      10x+1+59=18010x + 1 + 59 = 180.
      10x+60=18010x + 60 = 180.
      10x=12010x = 120.
      x=12x = 12.
    • For 2y12y - 1:
      2y1+59=1802y - 1 + 59 = 180.
      2y+58=1802y + 58 = 180.
      2y=1222y = 122.
      y=61y = 61.
    • For z7z - 7:
      Opposite angles in a rhombus are equal.
      z7=59z - 7 = 59.
      z=59+7=66z = 59 + 7 = 66.

    Answer:
    x=12x = 12,
    y=61y = 61,
    z=66z = 66.


Let me know if you want any part explained further!
Here are five related questions to deepen understanding:

  1. What is the key property of diagonals in a rhombus, and how does it differ from that in a parallelogram?
  2. How do you calculate angles in a parallelogram if one angle is given?
  3. Why are adjacent angles in a rhombus always supplementary?
  4. What happens to the diagonal intersection angles if the rhombus is a square?
  5. How do you find missing values in a rhombus if only one diagonal length is given?

Tip: Always verify relationships between angles or sides in geometric figures by referring to their defining properties!

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Math Problem Analysis

Mathematical Concepts

Properties of parallelograms
Properties of rhombuses
Supplementary angles
Diagonal bisection

Formulas

Diagonals of parallelograms bisect each other: CG = GE, RU = RT/2
Adjacent angles in a rhombus are supplementary: angle1 + angle2 = 180°

Theorems

Diagonal bisection property of parallelograms
Opposite angles in rhombuses are equal
Supplementary angles in quadrilaterals

Suitable Grade Level

Grades 8-10