Math Problem Statement

In rectangle ABCD, find m∠BCD. If AB = 7, then CD = ___. If AC = 9, then BD = ___. If BX = 8, then AC = ___. In rhombus EFGH, if EF = 10, then EH = ___. Find m∠GOH. If OH = 9, then FH = ___. If m∠FEH = 65, then m∠FGH = ___.

Solution

Let's go through the questions one by one and provide the necessary solutions:

20. In rectangle ABCD, find mBCDm \angle BCD.

  • The diagram shows a rectangle, and since BCD\angle BCD is part of a right triangle formed by the diagonal of the rectangle, BCD\angle BCD is 45°. This is because diagonals of a rectangle bisect the angles, and each angle formed by the diagonal is 45° in a rectangle.
  • Answer: mBCD=45m \angle BCD = 45^\circ.

21. If AB=7AB = 7, then CD=______CD = \_\_\_\_\_\_.

  • In a rectangle, opposite sides are equal. Therefore, if AB=7AB = 7, then CD=ABCD = AB because ABCDAB \parallel CD.
  • Answer: CD=7CD = 7.

22. If AC=9AC = 9, then BD=______BD = \_\_\_\_\_\_.

  • In a rectangle, the diagonals are congruent. Therefore, AC=BDAC = BD. If AC=9AC = 9, then BD=9BD = 9.
  • Answer: BD=9BD = 9.

23. If BX=8BX = 8, then AC=______AC = \_\_\_\_\_\_.

  • The diagram shows that BXBX is half of the diagonal, and since diagonals of a rectangle are equal, AC=2×BXAC = 2 \times BX.
  • Answer: AC=16AC = 16.

24. In rhombus EFGH, if EF=10EF = 10, then EH=______EH = \_\_\_\_\_\_.

  • In a rhombus, all sides are congruent. Therefore, EH=EFEH = EF. Since EF=10EF = 10, we have:
  • Answer: EH=10EH = 10.

25. Find mGOHm \angle GOH.

  • In a rhombus, the diagonals bisect each other at right angles. Thus, mGOH=90m \angle GOH = 90^\circ.
  • Answer: mGOH=90m \angle GOH = 90^\circ.

26. If OH=9OH = 9, then FH=______FH = \_\_\_\_\_\_.

  • In a rhombus, diagonals bisect each other. Therefore, OHOH is half of the full diagonal FHFH. So, FH=2×OH=2×9=18FH = 2 \times OH = 2 \times 9 = 18.
  • Answer: FH=18FH = 18.

27. If mFEH=65m \angle FEH = 65^\circ, then mFGH=______m \angle FGH = \_\_\_\_\_\_.

  • In a rhombus, opposite angles are equal, and the sum of adjacent angles is 180°. Since FEH+FGH=180\angle FEH + \angle FGH = 180^\circ, we can calculate mFGH=18065=115m \angle FGH = 180^\circ - 65^\circ = 115^\circ.
  • Answer: mFGH=115m \angle FGH = 115^\circ.

Would you like further details or clarifications on any of these? Here are five related questions to explore further:

  1. What are the properties of a rhombus that distinguish it from a square?
  2. How do you calculate the length of the diagonal in a rectangle given the side lengths?
  3. Why are the diagonals of a rectangle always congruent?
  4. How do the diagonals of a rhombus affect its symmetry and angles?
  5. Can you explain why opposite angles in a rhombus are always equal?

Tip: In any quadrilateral with equal diagonals, such as rectangles, the properties of symmetry help simplify many angle and length calculations.

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Math Problem Analysis

Mathematical Concepts

Properties of Rectangles
Properties of Rhombuses
Congruent Diagonals
Bisected Angles
Right Triangles

Formulas

Diagonals of a rectangle bisect each other
Congruent diagonals in a rectangle (AC = BD)
Sum of angles in a triangle = 180°
Sum of adjacent angles in a rhombus = 180°
Bisected diagonals in a rhombus

Theorems

Rectangle Diagonal Bisect Theorem
Congruent Diagonal Theorem
Rhombus Diagonal Bisect Theorem

Suitable Grade Level

Grades 7-9