To solve the expression \(\log 0 / 0001 - 2\log 100 + \log 1\), let's break it down step by step.

### 1. Evaluate each logarithm:

- **\(\log 0 / 0001\)**: 
   - First, note that \(\log(0 / 0001)\) is \(\log(1)\), since \(0 / 0001\) simplifies to \(1\).
   - \(\log(1) = 0\) because any base logarithm of 1 is always 0.

- **\(2 \log 100\)**:
   - \(\log 100\) (assuming base 10) equals 2, since \(10^2 = 100\).
   - So, \(2 \log 100 = 2 \times 2 = 4\).

- **\(\log 1\)**:
   - \(\log 1 = 0\) because, as mentioned earlier, the logarithm of 1 in any base is 0.

### 2. Plug in the evaluated logarithms:

\[
\log 0 / 0001 - 2\log 100 + \log 1 = 0 - 4 + 0
\]

### 3. Simplify the expression:

\[
0 - 4 + 0 = -4
\]

So, the final answer is **\(-4\)**.

Would you like more details on any step or have any questions?

Here are 5 related questions:
1. What is the logarithm of a negative number?
2. How do you simplify logarithmic expressions with different bases?
3. What is the value of \(\log 10^3\)?
4. How does the change of base formula work in logarithms?
5. How do you graph logarithmic functions?

**Tip:** Always check the base of the logarithm before starting your calculations to avoid errors.

Learn how to solve the logarithmic expression log0/0001 - 2log100 + log1 step-by-step with detailed explanations and examples. This problem covers logarithm properties, including logarithm of zero, logarithm of one, and logarithm of 100. Suitable for students in Grades 10-12.

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