To solve the expression $\log 0 / 0001 - 2\log 100 + \log 1$, let's break it down step by step.

1. Evaluate each logarithm:

• $\log 0 / 0001$:

  • First, note that $\log(0 / 0001)$ is $\log(1)$, since $0 / 0001$ simplifies to $1$.
  • $\log(1) = 0$ because any base logarithm of 1 is always 0.

• $2 \log 100$:

  • $\log 100$ (assuming base 10) equals 2, since $10^2 = 100$.
  • So, $2 \log 100 = 2 \times 2 = 4$.

• $\log 1$:

  • $\log 1 = 0$ because, as mentioned earlier, the logarithm of 1 in any base is 0.

2. Plug in the evaluated logarithms:

$\log 0 / 0001 - 2\log 100 + \log 1 = 0 - 4 + 0$

3. Simplify the expression:

$0 - 4 + 0 = -4$

So, the final answer is $-4$.

Would you like more details on any step or have any questions?

Here are 5 related questions:

1. What is the logarithm of a negative number?
2. How do you simplify logarithmic expressions with different bases?
3. What is the value of $\log 10^3$?
4. How does the change of base formula work in logarithms?
5. How do you graph logarithmic functions?

Tip: Always check the base of the logarithm before starting your calculations to avoid errors.