The problem given is:

$\log_6 x = 3$

To solve for $x$, we rewrite this logarithmic equation in its exponential form. The logarithmic statement $\log_6 x = 3$ implies:

$x = 6^3$

Calculating this:

$x = 216$

So, the solution is:

$x = 216$

Would you like a more detailed explanation or have any other questions?

Here are 5 related questions that could further expand on this concept:

1. How do you convert logarithmic equations to exponential form in general?
2. What is the general formula for solving $\log_b x = y$?
3. How do logarithms with different bases relate to each other (e.g., converting $\log_6 x$ to base 10)?
4. How would you solve a logarithmic equation if the logarithm has an unknown base?
5. What is the significance of logarithmic functions in real-world applications?

Tip: Remember, $\log_b x = y$ is the same as saying $b^y = x$. This conversion between logarithmic and exponential forms is crucial in solving logarithmic equations.