We are solving the equation:

$\log_3(x + 7) = 2$

Step-by-step solution:

1. Rewrite the logarithmic equation in exponential form: Using the property of logarithms $\log_b(a) = c$ implies $b^c = a$, we rewrite: $x + 7 = 3^2$

2. Simplify the exponential expression: $x + 7 = 9$

3. Solve for $x$: Subtract $7$ from both sides: $x = 9 - 7 = 2$

Final Answer:

The correct solution is: $x = 2$

Thus, the correct option is B.

Do you want further details or have any questions?
Here are 5 related questions to practice on:

1. Solve $\log_4(x - 5) = 3$ for $x$.
2. Rewrite $\log_2(32) = 5$ in exponential form and verify.
3. What is the solution to $\log_5(2x + 1) = 2$?
4. Explain the general steps to solve $\log_b(f(x)) = c$ equations.
5. Solve $\log_{10}(x + 4) = 1$ for $x$.

Tip: Always check that the argument inside the logarithm (e.g., $x + 7$) remains positive for the solution to be valid!