Math Problem Statement

its log base 3 not log base 8

Solution

Thank you for the clarification. Let's solve the problem correctly with the base 3:

Problem:

log3(log2x)=1\log_3 (\log_2 x) = 1

Step 1: Convert the logarithmic equation to an exponential equation

The equation log3(log2x)=1\log_3 (\log_2 x) = 1 can be rewritten using the definition of logarithms:

log2x=31\log_2 x = 3^1

Step 2: Simplify the equation

Since 31=33^1 = 3, we have:

log2x=3\log_2 x = 3

Step 3: Solve for xx

To solve for xx, rewrite the logarithmic equation in its exponential form:

x=23x = 2^3

Step 4: Calculate the value of xx

Now, calculate 232^3:

23=82^3 = 8

Final Answer

Thus, the correct solution to the equation is:

8\boxed{8}

Would you like further details or have any additional questions?

Here are 5 related questions to consider:

  1. How do you identify the base of a logarithm and use it in solving equations?
  2. What is the importance of converting logarithmic equations into exponential form?
  3. How would the solution change if the original equation was log3(log2x)=2\log_3 (\log_2 x) = 2 instead?
  4. What steps would you follow if the equation involved a logarithm with a base greater than 10?
  5. How does the logarithm base affect the solution of the equation?

Tip: When working with logarithms, carefully check the base to ensure the correct conversion to an exponential form. This helps in avoiding mistakes during calculations.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Equations

Formulas

Logarithm definition
Exponential equation conversion

Theorems

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Suitable Grade Level

High School