To solve the equation $\ln(x) = 2.896$, we can rewrite it in exponential form:

$x = e^{2.896}$

Now, we calculate $e^{2.896}$:

$x \approx 18.091$

Thus, the solution is:

$x \approx 18.091$

Would you like more details or have any questions?

Here are 5 related questions you might find helpful:

1. How do you solve an equation with a natural logarithm and an additional constant?
2. What is the general approach for solving logarithmic equations?
3. How do you graph logarithmic functions?
4. What are the properties of the natural logarithm $\ln(x)$?
5. How is the base $e$ used in real-world applications like growth and decay?

Tip: Remember, $\ln(x)$ is the natural logarithm, which means it's the logarithm with base $e \approx 2.718$.