It seems there might be a formatting issue with the equation. Based on the context, it looks like you want to solve the equation $e^x = 2.984$ and round the solution to four decimal places.

Let's solve it:

1. Start with the equation:

$e^x = 2.984$

2. Take the natural logarithm (ln) of both sides to solve for $x$:

$\ln(e^x) = \ln(2.984)$

3. Simplify the left side using the logarithm property $\ln(e^x) = x$:

$x = \ln(2.984)$

4. Calculate the natural logarithm:

$x \approx \ln(2.984) \approx 1.0932$

So, the solution to the equation $e^x = 2.984$ is $x \approx 1.0932$ when rounded to four decimal places.

Would you like any further explanation or details on this?

Here are five related questions:

1. How would you solve the equation $e^x = 7.5$?
2. What is the significance of the natural logarithm in solving exponential equations?
3. How can you use the property $\ln(ab) = \ln(a) + \ln(b)$ in solving logarithmic equations?
4. How does the graph of $y = e^x$ behave, and what does it tell you about solutions to equations like this?
5. What are some practical applications of solving equations involving $e^x$?

Tip: Always remember to round your final answer only at the end to avoid rounding errors during intermediate steps.