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We are given the system of equations:

\[
\begin{aligned}
x + y &= -6 \\
y &= -3x
\end{aligned}
\]

To solve this system by the substitution method, follow these steps:

### Step 1: Substitute the second equation into the first
Since \( y = -3x \), substitute this expression for \( y \) in the first equation:

\[
x + (-3x) = -6
\]

Simplifying:

\[
x - 3x = -6 \implies -2x = -6
\]

### Step 2: Solve for \( x \)
Divide both sides of the equation by \(-2\):

\[
x = \frac{-6}{-2} = 3
\]

### Step 3: Substitute \( x = 3 \) back into the equation for \( y \)
Using the second equation \( y = -3x \):

\[
y = -3(3) = -9
\]

### Step 4: Solution as an ordered pair
The solution to the system is \( (x, y) = (3, -9) \).

### Final Answer:
The solution set is \((3, -9)\), which corresponds to option **A**.

Would you like further clarification on any step? Here are 5 related questions for more practice:

1. How would you solve the same system using the elimination method?
2. What would the solution look like if the equations represented parallel lines?
3. How do you recognize if a system of equations has no solution or infinite solutions?
4. Can substitution always be used to solve any system of linear equations?
5. How does graphing help visualize the solution to a system of equations?

**Tip:** When solving systems by substitution, always simplify one equation first if possible, to make substitution easier.

Solve the system by the substitution method: x + y = -6, y = -3x. Select the correct choice from A, B, or C.

This problem involves solving a system of linear equations using the substitution method. Learn how to substitute one equation into another and solve for the variables step-by-step. The problem involves key algebraic concepts, including solving for x and y, and is suitable for students in Grades 8-10.

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