The image contains a set of linear equations, and you asked to solve them using substitution. I'll go through each pair of equations step by step.

1. Equations:

$\text{1. } -x + y = 1$ $2x + y = -2$

Step 1: Solve the first equation for $y$: $y = x + 1$

Step 2: Substitute $y = x + 1$ into the second equation: $2x + (x + 1) = -2$ $3x + 1 = -2$ $3x = -3 \quad \Rightarrow \quad x = -1$

Step 3: Substitute $x = -1$ back into $y = x + 1$: $y = -1 + 1 = 0$

Solution for the first system: $x = -1, \quad y = 0$

2. Equations:

$\text{2. } 2x + 2y = 3$ $x - 4y = -1$

Step 1: Simplify the first equation by dividing by 2: $x + y = \frac{3}{2}$

**Step 2: Solve for $x$: