It looks like there's a small typo in the equation you provided. I'm assuming you meant:

$3(2x + 5) - 5(4x - 1) = -8$

I'll solve it step by step:

Step 1: Expand both sides.

$3(2x + 5) = 6x + 15$ $-5(4x - 1) = -20x + 5$

So, the equation becomes: $6x + 15 - 20x + 5 = -8$

Step 2: Combine like terms.

$(6x - 20x) + (15 + 5) = -8$ $-14x + 20 = -8$

Step 3: Isolate the variable term.

Subtract 20 from both sides: $-14x = -8 - 20$ $-14x = -28$

Step 4: Solve for $x$.

Divide both sides by -14: $x = \frac{-28}{-14}$ $x = 2$

Final answer: $x = 2$

Would you like more details or have any questions?

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Here are 5 related questions to extend this concept:

1. What if the equation was $3(2x + 5) = 5(4x - 1)$?
2. How would you solve an equation with fractions, like $\frac{3}{4}(2x + 5) = \frac{5}{2}(4x - 1)$?
3. How do you verify the solution of an equation?
4. What happens when equations have no solution or infinite solutions?
5. How do you solve inequalities instead of equations?

Tip: Always distribute terms and simplify step by step before combining like terms when solving equations.