It looks like there's a small typo in the equation you provided. I'm assuming you meant:

\[ 3(2x + 5) - 5(4x - 1) = -8 \]

I'll solve it step by step:

### Step 1: Expand both sides.
\[
3(2x + 5) = 6x + 15
\]
\[
-5(4x - 1) = -20x + 5
\]

So, the equation becomes:
\[
6x + 15 - 20x + 5 = -8
\]

### Step 2: Combine like terms.
\[
(6x - 20x) + (15 + 5) = -8
\]
\[
-14x + 20 = -8
\]

### Step 3: Isolate the variable term.
Subtract 20 from both sides:
\[
-14x = -8 - 20
\]
\[
-14x = -28
\]

### Step 4: Solve for \( x \).
Divide both sides by -14:
\[
x = \frac{-28}{-14}
\]
\[
x = 2
\]

### Final answer: \( x = 2 \)

Would you like more details or have any questions?

---

Here are 5 related questions to extend this concept:

1. What if the equation was \( 3(2x + 5) = 5(4x - 1) \)?
2. How would you solve an equation with fractions, like \( \frac{3}{4}(2x + 5) = \frac{5}{2}(4x - 1) \)?
3. How do you verify the solution of an equation?
4. What happens when equations have no solution or infinite solutions?
5. How do you solve inequalities instead of equations?

**Tip:** Always distribute terms and simplify step by step before combining like terms when solving equations.

Learn how to solve the linear equation 3(2x + 5) - 5(4x - 1) = -8 using the distributive property and combining like terms. This step-by-step solution covers key algebraic concepts, perfect for students in Grades 8-10.

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