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The image contains the equation \( 9u = 16 + u \). Let's solve it step by step.

### Step-by-step solution:
1. Subtract \( u \) from both sides:
   \[
   9u - u = 16
   \]
   This simplifies to:
   \[
   8u = 16
   \]

2. Divide both sides by 8:
   \[
   u = \frac{16}{8}
   \]
   Simplifying further:
   \[
   u = 2
   \]

The solution is \( u = 2 \).

Would you like more details or further clarification?

### Here are some related questions:
1. How would you solve if the equation were \( 9u = 16 - u \)?
2. What happens if the equation is \( 9u + 3 = 16 + u \)?
3. How can you check if \( u = 2 \) is correct by substituting it back into the original equation?
4. How do equations like \( 9u = 16 + u \) relate to linear equations in general?
5. How would the solution change if there were a fraction involved, like \( \frac{9u}{2} = 16 + u \)?

### Tip:
Always check your solution by substituting it back into the original equation to confirm it satisfies the equation.

Solve for u in the equation 9u = 16 + u and simplify your answer.

Learn how to solve the linear equation 9u = 16 + u with a detailed step-by-step solution. This problem covers key algebraic concepts related to linear equations and is suitable for students in Grades 6-8.

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