To solve the equation \( 8x + 6 = 2y \) for \( y \), we need to isolate \( y \).

### Steps:
1. Start with the given equation:
   \[
   8x + 6 = 2y
   \]

2. Subtract 6 from both sides to move the constant to the left:
   \[
   8x = 2y - 6
   \]

3. Now divide both sides of the equation by 2 to isolate \( y \):
   \[
   y = 4x + 3
   \]

Thus, the equation solved for \( y \) is:
\[
y = 4x + 3
\]

Would you like a detailed explanation of the steps, or do you have any questions?

Here are 5 related questions to consider:
1. How would you solve for \( x \) in terms of \( y \)?
2. What is the slope of the line represented by \( y = 4x + 3 \)?
3. What are the \( x \)- and \( y \)-intercepts of this line?
4. How would you graph the equation \( y = 4x + 3 \)?
5. How does the form \( y = 4x + 3 \) compare to the standard form of a linear equation?

**Tip:** In linear equations, isolating one variable helps identify the slope and intercepts, which are useful for graphing the equation.

Learn how to solve the linear equation 8x + 6 = 2y and express y in terms of x. This solution covers key algebra concepts such as isolating variables and applying the slope-intercept form. Suitable for students in Grades 7-9.

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