To solve for \( q \) in the equation:

\[
6q - q - 2q - 1 = 29
\]

let’s simplify the equation step by step.

### Step 1: Combine like terms
Combine the terms involving \( q \):

\[
6q - q - 2q = 3q
\]

So, the equation now becomes:

\[
3q - 1 = 29
\]

### Step 2: Add 1 to both sides
To isolate the term with \( q \):

\[
3q - 1 + 1 = 29 + 1
\]

\[
3q = 30
\]

### Step 3: Divide both sides by 3
\[
q = \frac{30}{3}
\]

\[
q = 10
\]

### Final Answer:
\[
q = 10
\]

Would you like more details or have any questions?

### Related Questions:
1. How would the solution change if the constant term was different?
2. What if the equation was \( 6q - q + 2q - 1 = 29 \)?
3. How can you check if your solution for \( q \) is correct?
4. What happens if the terms involving \( q \) had coefficients like decimals or fractions?
5. How would the solution differ if the equation included terms like \( q^2 \)?

### Tip:
When solving equations, always combine like terms first to simplify the equation—it makes solving much easier!

Solve for q.
6q – q – 2q – 1 = 29
q=

Learn how to solve the linear equation 6q - q - 2q - 1 = 29 step by step. This example focuses on combining like terms and isolating the variable to find the solution, q = 10. Ideal for students in Grades 6-8.

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