Let's solve the equation:

\[
44 = 1x - 14
\]

### Step 1: Add 14 to both sides.
\[
44 + 14 = 1x
\]
\[
58 = 1x
\]

### Step 2: Simplify the equation.
Since \(1x\) is just \(x\), we get:
\[
x = 58
\]

### Final Answer:
\[
x = 58
\]

Do you have any questions or want a more detailed explanation?

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Here are five related questions to explore:

1. What if the equation was \(44 = 2x - 14\)?  
2. How would you solve for \(x\) if the equation included fractions, like \(44 = \frac{1}{2}x - 14\)?  
3. How do you handle equations with variables on both sides, e.g., \(3x - 14 = 2x + 5\)?  
4. How do you solve a quadratic equation like \(x^2 - 14x + 44 = 0\)?  
5. What happens when equations include absolute values, like \(|1x - 14| = 44\)?  

**Tip:** When solving equations, always perform the same operation on both sides to maintain equality!

Learn how to solve the linear equation 44 = 1x - 14 with a step-by-step guide. This problem covers essential algebra concepts, such as solving for x using the addition property of equality. Suitable for students in Grades 6-8.

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