Let's solve the equation \( 3(z - 2) = -3 \).

### Step 1: Distribute the 3 on the left-hand side
\[
3z - 6 = -3
\]

### Step 2: Add 6 to both sides to isolate the term with \( z \)
\[
3z = -3 + 6
\]
\[
3z = 3
\]

### Step 3: Divide both sides by 3 to solve for \( z \)
\[
z = \frac{3}{3}
\]
\[
z = 1
\]

Thus, the solution is \( z = 1 \).

Would you like more details on the solution? Here are some related questions to further explore:

1. How do you solve equations involving parentheses and distribution?
2. What happens when you have variables on both sides of an equation?
3. Can equations be solved differently without distributing?
4. How do you check if a solution is correct?
5. What are the common mistakes when solving linear equations?

**Tip:** Always verify your solution by substituting it back into the original equation to ensure it satisfies the equation.

This page explains how to solve the linear equation 3(z−2) = −3 step-by-step, using key algebraic concepts such as the distributive property and basic equation solving techniques. Ideal for students in Grades 6-8.

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